I know that when you have a chiral center, you rank the 4 substituents and view the compound with the lowest priority group in the back, and assign it an R (right) or S (left) orientation. Lets assume we have a compound where the #4 substituent is H and it has a dashed line so it is already in the back, making it easy to determine R or S. If the H were to have a wedge instead, then you do the same thing but flip the orientation so S becomes R and R becomes S. Now what happens when the H bond is in the plane (straight line)?
From what I remember, you redraw the compound leaving all the bond connectivities (lines, dashed, wedge) exactly how they are, except you would switch the H with the compound that has the dashed line, and then determine R or S. Is this correct?
From what I remember, you redraw the compound leaving all the bond connectivities (lines, dashed, wedge) exactly how they are, except you would switch the H with the compound that has the dashed line, and then determine R or S. Is this correct?