Dice Question

[1999TL]

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A certain Board game is playedby rolling a pair of fair sex-sided dice and the moving one's piece forward the number of spaces indicated by the sum showing on the dice. A player is "froze if her opponent's piece comes to rest in the space already occupied by her piece. If player is about to roll and is currently six spaces behind player B, what isthe probability that player B will be frozen after player A rolls?

A. 1/12
B. 5/36
C. 1/6
D 1/3
E 17/36

I think the answer is wrong for some reason, but I'll see what you guys think first.

 

[pbure9]

Is the answer B?

 

[1999TL]

It's B, but I got C. How come they are only counting 3/3 once?

 

[JWD1023]

(5+1); (1+5); (4+2); (2+4); (3+3)...there is only one (3) on each piece...the first combinations are not switched around...they are rolled again

 

[1999TL]

yah, I figured it out later and realized how dumb the question was. Thanks.