Difficult but important pressure questions

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stester77s

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If there is a closed chamber with the following reaction:

CO2 (g) + C (s)---> 2CO (g)

And the reaction chamber is made bigger by a piston that expands the reaction chamber, and the temperature is held constant, then the volume increases and the overall pressure decreases.


But does the reaction get shifted in any direction? Does the reaction shift to the right? If so, please explain why. I understand that the reaction should not shift because the partial pressures of either gas relatively do not change. They both decrease, but in equal percentages. But this may be incorrect. Please explain.
 
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it is not that hard actually, think of in terms of le chatelier principle. When you increase the volume, the pressure goes down initially due to pv=nrt. If the pressure goes down, the le chatelier principle dictates that the system needs to adjust to counter the effect. The initial effect was drop in pressure, then the reaction will shift to left or right such that pressure will be increased? Now, I will leave the rest to you. I will tell you if you are correct after you try.
 
One more hint for you. Actually, I am almost giving out the answer right now. Count the number of gas molecules. This info is enough to answer your question. I will explain in terms of partial pressure equilibrium constant after you answer
 
One more hint for you. Actually, I am almost giving out the answer right now. Count the number of gas molecules. This info is enough to answer your question. I will explain in terms of partial pressure equilibrium constant after you answer
You dun gave it away lel
 
??? Confused !!! Your comment is so random
Oh forget it... I was just saying you gave a really good hint about the comparison of moles of gas in the reaction and remembering Le Chat's principle. Sorry for the confusion 🙁
 
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