Do we have to memorize physical constants for the PS section?

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pharm1234

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Do we have to memorize physical constants for the PS section? Does the MCAT give us any formulas?

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I was also wondering the same thing. On the Kaplan practice tests, they sometimes give us constants, and sometimes they expect us to know them. Does anyone know which ones we need to memorize?
 
I highly doubt you would need to know any physical constants for the MCAT, except for, mabye, avrogado's number. I've taken 5/6 AAMC exams and none of them have required any constants.
 
pharm1234 said:
Do we have to memorize physical constants for the PS section? Does the MCAT give us any formulas?

To rely on one's mastery of material is better than one's reliance on chance. Passages may provide you with required formulae and constants. Discreets may not.

Dedicate some of your time towards the memorization of these constants; (they aren't very many) and you will reap the rewards of freedom from doubt. A formula is without any worth when one does not have the values with which to represent it.
 
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pharm1234 said:
Do we have to memorize physical constants for the PS section? Does the MCAT give us any formulas?
i recall learning in my kaplan course that the only constants you MUST memorize are acceleration due to gravity and avogadro's number. but that was a while ago so i might not be remembering correctly.
 
I teach physics for princeton review and from everything I have seen, only two constants need to be known from memory: g and c.

g = 10 m/s^2 (good enough approx. like Brett said)
c = 3 x 10^8 m/s

any other constants need not be known from memory, although it doesn't hurt to remember any extra ones you may use, such as coulomb's constant (9x10^9) or the elementary charge e (1.6x10^-19). It would save you the time of searching through a passage to retrieve them, as they would be given.

As far as gchem, when I studied I remember memorizing only avogadro....no potentials or heats of formation or any of that. Oh that and the heat capacity of H20 is 1 cal/g*C. I think that was it.
 
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