- Joined
- Jan 16, 2016
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Hey everyone,
I was working through a QVault quesiton, and one of the answers was pretty interesting. They stated that solids don't affect equilibrium (with which I agree), but "removing all the solid from a solution, by filtration, would mean that the solution is no longer at equilibria"
Logically, what they say makes sense to me. If we had Ksp for something like Mg(OH)2, I feel like if all the solid reactant was removed, the products would have to shift to reattain equilibrium; however, when one looks at the equilibria expression, it's clear that the solid isn't included, so I do not understand what exactly happens.
In summary, would equilibria change if all the solid was removed, and how does this relate to the equilibria expression? Any input is appreciated.
Thanks!
I was working through a QVault quesiton, and one of the answers was pretty interesting. They stated that solids don't affect equilibrium (with which I agree), but "removing all the solid from a solution, by filtration, would mean that the solution is no longer at equilibria"
Logically, what they say makes sense to me. If we had Ksp for something like Mg(OH)2, I feel like if all the solid reactant was removed, the products would have to shift to reattain equilibrium; however, when one looks at the equilibria expression, it's clear that the solid isn't included, so I do not understand what exactly happens.
In summary, would equilibria change if all the solid was removed, and how does this relate to the equilibria expression? Any input is appreciated.
Thanks!