I came across this question:
What change is observed in the force exerted on charged particle P in a uniform electric field when it is moved closer to the plate on the left, so that the distance r separating them is reduced by half?
A. The force doubles, if the charge is negative.
B. The force doubles, if the charge is positive.
C. The force increases by a factor of 4, regardless of the type of charge.
D. The force does not change, regardless of the magnitude or sign of the charge.
The answer is D but I'm confused why it would not be A or B
I thought since E=V/d then if the distance is reduced by half then E would be increased by 2. Consequently, since F= Eq, I thought if E doubles than the force doubles.
Can someone explain why this would not be correct?
What change is observed in the force exerted on charged particle P in a uniform electric field when it is moved closer to the plate on the left, so that the distance r separating them is reduced by half?
A. The force doubles, if the charge is negative.
B. The force doubles, if the charge is positive.
C. The force increases by a factor of 4, regardless of the type of charge.
D. The force does not change, regardless of the magnitude or sign of the charge.
The answer is D but I'm confused why it would not be A or B
I thought since E=V/d then if the distance is reduced by half then E would be increased by 2. Consequently, since F= Eq, I thought if E doubles than the force doubles.
Can someone explain why this would not be correct?