Endothermic vs Exothermic Conundrum (TBR Chem II Gas Passage X #70)

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corporateflea

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While studying for endothermic vs exothermic, I've run into a bit of a conundrum.

Endothermic absorbs heat as a reactant and thus makes the "surrounding" colder (i.e. your finger touching the beaker). However, since the system ABSORBS heat, shouldn't the product of endothermic reaction be hotter than before?

Vice versa for exothermic. Heat is produced as a product and thus the beaker should be hot to touch, but the product itself should be colder than before since it has RELEASED heat into the surrounding from the SYSTEM.

What I'm I missing here?

As per TBR Chemistry II Gases chapter, #70, "An endothermic reaction results in a COOLER solution"

It should be stated An endothermic reaction results in a HOTTER solution but COOLER beaker containing it.

Right?
 
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just think about it this way... heat is just a reactant. so think about it in terms of equilibrium. if heat is a reactant (endothermic), the product that it forms will be use the heat as a reactant - and thus be cooler - when it forms. So if you INCREASE the temp of an endothermic reaction, you form the product. Similarly, if you increase the temperature of an exothermic reaction, the reverse reaction will occur.

and 'heat' doesn't necessarily mean hot/cold. It is energy. So the temperature of the solution/beaker isn't really what its going for here
 
An endothermic reaction means it USES heat to form the product, so the solution is colder because heat is being taken away to form it. You need to consolidate your understanding of what a reactant and a product is and what it means when heat is a reactant and a product.
 
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