energy transfer question

[Smooth Operater]

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if 500 g copper at 300 Celsius is placed in contact w/ an equal mass of aluminum, at 0 Celsius, what will be the final temperature of the whole mass, assuming no heat loss to surroundings (suppose it takes twice as much heat to heat 1 gram of aluminum as it does to heat a gram of copper) ?

Anyone knows how to solve it? Thank you.















The correct answer is 100 Celisus.

 

[allstardentist]

Just use the conservation of energy principle, all the heat lost by the copper will be gained by th e aluminum since no heat is lost to the surroundings.

heat lost by copper = heat gained by aluminum
mass of copper*specific heat of copper * (delta T)= mass of aluminum* specific heat of aluminum.

m*c*(300-x)= m*2c*(x-0) since specific heat of alu. is twice copper and mass is same

m & c cancel out, and if u solve for x, x=100

hope it helps