Equilibrium System Constants

[Xo1991]

---

Members do not see this ad.

This is in reference to a GC destroyer problem (#83 2013)

It gives an equilibrium system, and the answer key says that only temperature changes a K value, not a catalyst, etc. etc. I already knew that

But then, when they multiply the reaction by two (doubling concentrations?), then it says the Knew is 50^2. And when the reaction is reversed, it says the Knew = 1/Koriginal

When multiplying the reaction, is that the same as changing the concentration? This is confusing me, because I have been repeatedly told that the only thing that changes a rate constant is temperature.

What's going on?

 

[athomas]

Multiplying the reaction by two isn't multiplying concentration, it's the coefficients in the reaction given.

Say we have A + 2B --> C and none are pure liquids or solid

Our K for the forward reaction = [C]/([A]^2)

if we double the reaction to 2A + 4B ---> 2C

Our K for the forward reaction = [C]^2/([A]^2^4])

See how that is the same as K from the first reaction but square?