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A passenger stands on a scale which is inside an elevator. If the scale reads 110 pounds when the elevator is at rest, what would it read when the elevator begins to accelerate upwards at 3 ft/sec2
115 pounds
120 pounds
130 pounds
135 pounds
same magnitude as the normal force of the scale upward on the person.
Now consider the case of an upward acceleration of 3 ft/sec2. The net force on the person is now N - mg = N - 110 = ma, where N is the normal force of the scale upward on the person and we've used the fact that the person's weight is mg = 110. So we have a reading on the scale of N = 110 + ma. From mg = 110, we have m = 110/g = 110/32 (g = 32 ft/s2) . Thus, N = 110 + 3(110/32) , so N = 120 pounds.
Where the the 32 come from!!!
115 pounds
120 pounds
130 pounds
135 pounds
same magnitude as the normal force of the scale upward on the person.
Now consider the case of an upward acceleration of 3 ft/sec2. The net force on the person is now N - mg = N - 110 = ma, where N is the normal force of the scale upward on the person and we've used the fact that the person's weight is mg = 110. So we have a reading on the scale of N = 110 + ma. From mg = 110, we have m = 110/g = 110/32 (g = 32 ft/s2) . Thus, N = 110 + 3(110/32) , so N = 120 pounds.
Where the the 32 come from!!!