Dear SDN,
Can you guys please check my knowledge on galvanic and electrolytic cells? The following is modeled off a question from TBR CBT 6 question 46.
Zn2+ + 2e- = -.76 V
Cu2+ + 2e-= .34 V
If we have a galvanic cell that has Zn(s) as the reducing agent (in our anode) and Cu2+ as our oxidizing agent (in our cathode), t
hen electrons go from anode to cathode. Zn(s) dissociates and Cu2+ plates out. Cathode is positive and anode is negative.
However, if we were to apply a battery voltage, the cell becomes an electrolytic cell and the unfavorable rxn occurs:
Zn2+ is our oxidizing agent (in our cathode) and Cu(s) is now our reducing agent (in anode), e- still goes from anode to cathode.
Zn2+ plates out now and Cu(s) dissociates. So basically their roles change.According to definition, the anode of an electrolytic cell is positive and
the cathode is negative. Why is this so? Shouldn't the anode still be negative and the cathode still positive? Am I missing anything?
Can you guys please check my knowledge on galvanic and electrolytic cells? The following is modeled off a question from TBR CBT 6 question 46.
Zn2+ + 2e- = -.76 V
Cu2+ + 2e-= .34 V
If we have a galvanic cell that has Zn(s) as the reducing agent (in our anode) and Cu2+ as our oxidizing agent (in our cathode), t
hen electrons go from anode to cathode. Zn(s) dissociates and Cu2+ plates out. Cathode is positive and anode is negative.
However, if we were to apply a battery voltage, the cell becomes an electrolytic cell and the unfavorable rxn occurs:
Zn2+ is our oxidizing agent (in our cathode) and Cu(s) is now our reducing agent (in anode), e- still goes from anode to cathode.
Zn2+ plates out now and Cu(s) dissociates. So basically their roles change.According to definition, the anode of an electrolytic cell is positive and
the cathode is negative. Why is this so? Shouldn't the anode still be negative and the cathode still positive? Am I missing anything?