GC Dat Destroyer #7

[Muggs]

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The question asks what family the element Seaborgium (Sg) would be found in and I understand that it is in the transition metals. However, when the answer solution talks about Lanthanides and actinides, saying ...

"You will notice a "break" after La and Ac. These elements are the inner transition metals. Metals from 57-112 would be transition metals."

Are the "breaks" referring to 72-79 after La and 104-111 after Ac and that these breaks are the inner transition metals?

Also, does that also mean that the La and Ac periods are considered transition metals?

 

[Muggs]

Also, for question #65, which asks...

"Which element is the most electronegative?"

a. K
b. Mg
c. C
d. P
e. Br

So the trend for electronegativity is that it increases going up and across the PT towards F. In this case, how do you determine when an element's position in a period (closer to halogen) takes precedence over shell size. So, why is Br more electronegative than P?

 

[Mr. Thirsty]

Also, for question #65, which asks...

"Which element is the most electronegative?"

a. K
b. Mg
c. C
d. P
e. Br

So the trend for electronegativity is that it increases going up and across the PT towards F. In this case, how do you determine when an element's position in a period (closer to halogen) takes precedence over shell size. So, why is Br more electronegative than P?

It is to my understanding that groups hold precedence over periods when comparing for EN, unless the split is huge. So phosphorous would be more EN than Br but Al or Mg would not. I think Chad mentioned this.

 

[Muggs]

It is to my understanding that groups hold precedence over periods when comparing for EN, unless the split is huge. So phosphorous would be more EN than Br but Al or Mg would not. I think Chad mentioned this.

I'm a bit confused by your explanation. If "groups hold precedence over periods", why would P be more EN than Br? Do you mean the reverse: that the position in their period takes precedence?

Also I found this table of electronegativities and it seems that Br is more EN than P, so I guess it has to do with their position in a period (being closer to halogen) rather than shell size that takes precedence.

http://imgur.com/4gzFv

Can anyone confirm this?

 

[jaymin8]

Well, P is three "spots" away from F while Br is only two "spots" away. Also, remember groups have the same characteristics (as Chad stated in his videos). Noble gases don't like to react, halogens want to gain the extra electron, etc. So basically groups are more similar than shell size.

An example would be which is more electronegative....I or P...both are three "spots" away but since its a halogen it is more electronegative than P (but not by much I would assume).