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This is from Destroyer...
An Unknown metal of 50 grams is initially at 100 ˚C and dropped into a beaker of 200 grams of water at 30 ˚C. The final temperature of the system is 40 C. Find the specific heat of the metal if the heat of water is 4.2 J/g C.
I get that we have to set the equations equal to each other, but i dont get how to properly set the temperatures
m(metal)*c*∆T = m(water)*c(water)∆T
so... (this is the set up given in the solutions)
(50) c (100 - 30) = (200) (4.2) (40-30)
Can someone shed some light PLEASEEEEE???
An Unknown metal of 50 grams is initially at 100 ˚C and dropped into a beaker of 200 grams of water at 30 ˚C. The final temperature of the system is 40 C. Find the specific heat of the metal if the heat of water is 4.2 J/g C.
I get that we have to set the equations equal to each other, but i dont get how to properly set the temperatures
m(metal)*c*∆T = m(water)*c(water)∆T
so... (this is the set up given in the solutions)
(50) c (100 - 30) = (200) (4.2) (40-30)
Can someone shed some light PLEASEEEEE???