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Consider an acetate buffer, initially at the same pH as its pKa (4.76). When sodium hydroxide (NaOH) is mixed with this buffer, the:
7%
A:
pH remains constant.
12%
B: pH rises more than if an equal amount of NaOH is added to an acetate buffer initially at pH 6.76.
12%
C: pH rises more than if an equal amount of NaOH is added to unbuffered water at pH 4.76.
1%
D:sodium acetate formed precipitates because it is less soluble than acetic acid.
68%
E:[Correct]
ratio of acetic acid to sodium acetate in the buffer falls.
Can someone explain the reasoning behind the answers please for B/C. Also, E is correct b/c OH mixes with the buffer which lowers the ratio correct?
7%
A:
pH remains constant.
12%
B: pH rises more than if an equal amount of NaOH is added to an acetate buffer initially at pH 6.76.
12%
C: pH rises more than if an equal amount of NaOH is added to unbuffered water at pH 4.76.
1%
D:sodium acetate formed precipitates because it is less soluble than acetic acid.
68%
E:[Correct]
ratio of acetic acid to sodium acetate in the buffer falls.
Can someone explain the reasoning behind the answers please for B/C. Also, E is correct b/c OH mixes with the buffer which lowers the ratio correct?
Last edited: