itzsohz New Member 10+ Year Member 15+ Year Member Sep 12, 2006 #1 Advertisement - Members don't see this ad find the pH of a 0.040 M NaCN solution. Given: K(a) of HCN is 5.0 x 10^(-10) a)11 b)8.7 c)5.3 d)12 e)3.4 i got this sH1t wrong 3 times... some1 help me 😡
Advertisement - Members don't see this ad find the pH of a 0.040 M NaCN solution. Given: K(a) of HCN is 5.0 x 10^(-10) a)11 b)8.7 c)5.3 d)12 e)3.4 i got this sH1t wrong 3 times... some1 help me 😡
itzsohz New Member 10+ Year Member 15+ Year Member Sep 12, 2006 #3 a they coverted in to K(b) first Upvote 0 Downvote
doc toothache Full Member 15+ Year Member Sep 14, 2006 #4 try this: 0.04 will ionize to give 0.04M of HCN (H+)(CN-): HCN=5.0 x 10 (-10) (H+)(CN-): 0.04=5.0 x 10(-10) =20 x 10(-12) (H+) =square root of ((20 x 10 (-12) solve for H and convert to pH Upvote 0 Downvote
try this: 0.04 will ionize to give 0.04M of HCN (H+)(CN-): HCN=5.0 x 10 (-10) (H+)(CN-): 0.04=5.0 x 10(-10) =20 x 10(-12) (H+) =square root of ((20 x 10 (-12) solve for H and convert to pH