GChem Question

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allstardentist

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Topscore and some other books say that when Keq=1, there is an equal number of reactants and products. But what if an equation was like this

2 A(aq) <---> 1B(aq) + 3 C(aq)

Then the Keq= [C]^3/[A]^2

when the Keq is 1, the number of products and reactants are not necessarily going to be equal.

What do you guys think?
 
Topscore and some other books say that when Keq=1, there is an equal number of reactants and products. But what if an equation was like this

2 A(aq) <---> 1B(aq) + 3 C(aq)

Then the Keq= [C]^3/[A]2

when the Keq is 1, the number of products and reactants are not necessarily going to be equal.

What do you guys think?




Keq is based on concentration NOT number of products. therefore the conc of B times the conc of C^3 ALL divided by the conc of A^2 will be one.

hope this helps.
 
from kaplan review notes(pg 849)

".....If the value of Keq is close to 1, an equilibrium mixture of products and reactants will contain approx equal amonts of reactants and products."


dunno what theyre referring to exactly, i assumed it was conc.

I thought it could refer to both # of moles and concentration b/c the solution should have a given volume.

All the books say that. So it must be true. but i dont know why.
 
Topscore and some other books say that when Keq=1, there is an equal number of reactants and products. But what if an equation was like this

2 A(aq) <---> 1B(aq) + 3 C(aq)

Then the Keq= [C]^3/[A]^2

when the Keq is 1, the number of products and reactants are not necessarily going to be equal.

What do you guys think?


What it means is that the total concentration of products is equal to the total concentration of reactants. In this case, [C]^3 = [A]^2.

aranjuez
 
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