Gchem question

[Predentknight]

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What is the Normality of a 3.0M solution of H2SO4?

I thought when determining Molarity of a substance you multiply by the Normality. Therefore in finding Normality wouldnt you divide by the equivalents? I have this all confused can someone please clear this up.

Ans. is 6


Also keep getting caught up on lechatliers problems. Does anyone have an easy simplified way of dealing with that principle. Thanks so much.😀

 

[arpitpatel86]

since there is 2 H atoms in there and and 3M concentration u have: 3M x 2(from the 2 H)= 6N

if u had something like 3M with NaOH and u want to know the Normality....its 3M x 1(from the 1 OH) which equals 3N now if there were 2 OH's it be 6N

hope that helps

 

[DRHOYA]

Its pretty simple when you think about it. N is greater than or equal to M. In a 3.0M solution of H2SO4, there are 2 H's that can go, so 3 x 2 = 6. This is also true for OH's. In a 2.0M solution of something like Fe2(OH)2, there are 2 OH's, so for N, 2.0M x 2OH's = 4N. Hope that helps.

Also N1V1 = N2V2. It is a similar equation to the familiar one M1V1 = M2V2, but when you have compounds like H2SO4, your can use normality instead of molarity.

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