GChem Question

[IdahoDoc]

---

Members don't see this ad.

What is the hybridization of As in AsF4-???

 

[Tina324]

is it sp3d?
if so, just draw the lewis and count the orbital (4 for the f bonds and 1 for the lone pair) so there are a total of 5 hybridized orbitals that combine 5 pure orbitals.

 

[nixon13]

the electronic geometry is octahedral and the molecular geometry is square planar. As=5 valence electrons F= 7(4)=28. 28+5=33 but dont forget about the - charge on the whole molecule giving it a total of 34. So you draw the molecule with the least electronegative atom in the middle (As) with the 4 F around it. Give all of the atoms and octet and then add the remaining lone pairs to the central atom. So if you give every atom an octet, you have 4 remaining electrons so 2 lone pairs around the central atom. Then you can memorize this chart to find the electronic and molecular geometries. On the DAT, read the question carefully and see if they want the MOLECULAR or ELECTRONIC geometries because sometimes you look past it and get an easy question wrong. Here is the link for the geometries.

http://intro.chem.okstate.edu/1314F00/Lecture/Chapter10/VSEPR.html

Hope this helps, good luck!

 

[IdahoDoc]

is it sp3d?
if so, just draw the lewis and count the orbital (4 for the f bonds and 1 for the lone pair) so there are a total of 5 hybridized orbitals that combine 5 pure orbitals.

where does the lone pair come from? I thought As had 3 valence electrons? To give a total of 32 with the F and the 1electron. Could you re explain please?

 

[nixon13]

you asked for the hybridization sorry, I wrote the wrong answer for that. Here is a link for hybridization...

http://faculty.smu.edu/whorsthe/VSEPR.pdf

 

[IdahoDoc]

the electronic geometry is octahedral and the molecular geometry is square planar. As=5 valence electrons F= 7(4)=28. 28+5=33 but dont forget about the - charge on the whole molecule giving it a total of 34. So you draw the molecule with the least electronegative atom in the middle (As) with the 4 F around it. Give all of the atoms and octet and then add the remaining lone pairs to the central atom. So if you give every atom an octet, you have 4 remaining electrons so 2 lone pairs around the central atom. Then you can memorize this chart to find the electronic and molecular geometries. On the DAT, read the question carefully and see if they want the MOLECULAR or ELECTRONIC geometries because sometimes you look past it and get an easy question wrong. Here is the link for the geometries.

http://intro.chem.okstate.edu/1314F00/Lecture/Chapter10/VSEPR.html

Hope this helps, good luck!

Thanks i don't know why i thought it had 3 v. electrons i know it has 5. thanks!

 

[nixon13]

As is in group 5 so it has 5 valence electrons. The group number for the elements indicates the number of valence e-. The doesnt include the group B elements just the group A.