gchem solution problem

Started by andyjl
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andyjl

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What is the normality of a 1M solution of H3PO4 titrated with CaCl2?

Ans: 1.5

Someone please explain
 
What is the normality of a 1M solution of H3PO4 titrated with CaCl2?

Ans: 1.5

Someone please explain

2PO43- + 3Ca2+ ----> Ca3(PO4)2

Calcium phosphate is insoluble by the way

1mol of phosphate reacts with 3/2 mol equiv. of Ca2+

N = 1(1.5) = 1.5
 
2PO43- + 3Ca2+ ----> Ca3(PO4)2

Calcium phosphate is insoluble by the way

1mol of phosphate reacts with 3/2 mol equiv. of Ca2+

N = 1(1.5) = 1.5
How do you know how to set up the equation that way and to ignore the other product HCl?
 
HCl will dissociate immediately...furthermore...chloride salts are soluble except for with Hg2 ++, Ag+, Pb++, Cu+...when you set up the equation you have to eliminate spectator ions. therefore...know the solubility rules...


However...the answer 1.5 assumes complete dissociation of H3PO4...don't really think of H3PO4 dissociating completely in Calcium Chloride

Here is another way to think of normailty

H3PO4 titrated with NaOH

1mol H3PO4 reacts with 3equiv NaOH/mol H3PO4
 
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With normality questions....just make sure you know the definition of normality.

N = mol x equiv/mol

Most of our study guides use normality for acid base titrations only and a chemical equation is not needed...

But for redox titrations...the equation is needed...look in your chemistry textbook for redox titration problems