Gen Chem ? from CDA prep book

[DDS2012]

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Hey guys, can anyone help me out with this one?

During a titration it was determined that 30.00 mL of a 0.100 M Ce4+ solution was required to react completely with 20.00 mL of a 0.150 M Fe2+ solution. Which one of the following reactions occurred?
A. Ce4+ + 3Fe2+ + H20 --> 3Fe3+ + CeO- + 2H+
B. 2Ce4+ + Fe2+ --> Fe4+ + 2Ce3+
C. Ce4+ + Fe2+ --> Fe3+ + Ce3+
D. Ce4+ + 2Fe2+ --> 2Fe3+ + Ce2+

The answer is C. Can anyone explain? Thanks!

 

[tastybeef]

Moles of Ce4+:
0.03L * (0.1 M) = 0.03 moles
Moles of Fe2+
0.02L * (0.15M) = 0.03 moles

They are in a 1 to 1 molar ratio, only C conveys that in the equation.