Gen-Chem Problem

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Ka = [H+][Conjugate Base]/[acid]

Ka = 2.0x10-5 = [H+][0.2]/[0.2] = [H+]=2.0x10-5

pH = -log[H+] = -log[2.0x10-5]

I don't have a calculator with me but i'm sure you can figure it out.
 
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