D Dr.9999 Full Member 10+ Year Member Joined Jul 22, 2009 Messages 72 Reaction score 1 Points 4,531 Pre-Dental Sep 22, 2012 #1 Advertisement - Members don't see this ad You have .2M of acetic acid and .2M of a weak base. What is the PH of the (H+) concentration? Ka= 2.0 x 10-5. Last edited: Sep 22, 2012
Advertisement - Members don't see this ad You have .2M of acetic acid and .2M of a weak base. What is the PH of the (H+) concentration? Ka= 2.0 x 10-5.
P Papasmurf1234 Full Member 10+ Year Member Joined Aug 7, 2011 Messages 524 Reaction score 68 Points 4,846 Sep 22, 2012 #2 Ka = [H+][Conjugate Base]/[acid] Ka = 2.0x10-5 = [H+][0.2]/[0.2] = [H+]=2.0x10-5 pH = -log[H+] = -log[2.0x10-5] I don't have a calculator with me but i'm sure you can figure it out. Upvote 0 Downvote
Ka = [H+][Conjugate Base]/[acid] Ka = 2.0x10-5 = [H+][0.2]/[0.2] = [H+]=2.0x10-5 pH = -log[H+] = -log[2.0x10-5] I don't have a calculator with me but i'm sure you can figure it out.
