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Gen Chem Question

Started by Farcus
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Farcus

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292. Find the element possessing the set of quantum numbers [5, l, -l, +l/2] for its last electron.
1) 31Ga 2) 47Ag 3) 50Sn 4) 81Tl 5) none of these
ANS: 5

How is this problem correct?

Ok primary quan number is 5 so 2👎^2=50 which make sense to be 3 right? since SN has 50 protons. and also 1 is the L then it means it has S and P orbitals that SN does have and -1 would mean Px. How is it None of the above?
 
292. Find the element possessing the set of quantum numbers [5, l, -l, +l/2] for its last electron.
1) 31Ga 2) 47Ag 3) 50Sn 4) 81Tl 5) none of these
ANS: 5

How is this problem correct?

Ok primary quan number is 5 so 2👎^2=50 which make sense to be 3 right? since SN has 50 protons. and also 1 is the L then it means it has S and P orbitals that SN does have and -1 would mean Px. How is it None of the above?

Five answer choices? You might want to reconsider the materials. While it's a good question, five answer choices is not realistic, so the materials may not be realistic.

n = 5 thus fifth shell
l = 1 thus p-orbital
ml = -1 so it's a px orbital
ms = +1/2, so it's spin up

This means that we need to look at the first element in the fifth row of the p-block to find the element with those quantum numbers for the last electron. That happens to be In, element 49.
 
thanks

but had the problem been [5, l, -l, + and - l/2]

it would of been SN right? since -1 mean Px which is either In or Sn but since there are two electrons now then it'll be SN right?

I know its not realistic I just found this online, I needed to brush up on my Gen Chem.