Gen Chem question
- Thread starter gatorPredent
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The stochiometric ratio is:
1:3:2
N2:H2:NH3
Since there is only 1 mole of H2 (limiting compound), divide everything by 3 which results in the following ratio:
1/3:1:2/3
This means that 1/3 mole of N2 and 1 mole of H2 will produce 2/3 mole of NH3.
I would approach it like this:
Since you need 3moles of H2 to react with 1mole N2, you know that H2 is limiting. Always use the limiting factor.
Since you have 1 mole of H2 and 3 moles of H2 are needed to yield 2 moles of NH3, do this:
1 mol H2 (have) * [ 2 moles NH3 / 3 moles H2 (needed)] = 2/3
Since you need 3moles of H2 to react with 1mole N2, you know that H2 is limiting. Always use the limiting factor.
Since you have 1 mole of H2 and 3 moles of H2 are needed to yield 2 moles of NH3, do this:
1 mol H2 (have) * [ 2 moles NH3 / 3 moles H2 (needed)] = 2/3
those are both good ways to approach this problem. Thank you kindly!
