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Gen Chem question

gatorPredent

Full Member
10+ Year Member
Nov 9, 2008
111
0
0
Florida
  1. Pre-Dental
Which is the best way to approach? 1 mole of N2 and 1 mole of H2 are mixed and allowed to react according to the equation N2+3H2 ------> 2NH3. Whats the max number of moles of NH3 that could be produced?
The answer is 2/3 but somehow i got 1/2
Thanks
 

ttran9229

Full Member
May 15, 2009
56
0
0
  1. Pre-Dental
Which is the best way to approach? 1 mole of N2 and 1 mole of H2 are mixed and allowed to react according to the equation N2+3H2 ------> 2NH3. Whats the max number of moles of NH3 that could be produced?
The answer is 2/3 but somehow i got 1/2
Thanks

The stochiometric ratio is:

1:3:2
N2:H2:NH3

Since there is only 1 mole of H2 (limiting compound), divide everything by 3 which results in the following ratio:

1/3:1:2/3

This means that 1/3 mole of N2 and 1 mole of H2 will produce 2/3 mole of NH3.
 

MTD52

Class of 2014
10+ Year Member
5+ Year Member
Sep 10, 2008
625
1
0
New Jersey
  1. Dental Student
I would approach it like this:

Since you need 3moles of H2 to react with 1mole N2, you know that H2 is limiting. Always use the limiting factor.

Since you have 1 mole of H2 and 3 moles of H2 are needed to yield 2 moles of NH3, do this:

1 mol H2 (have) * [ 2 moles NH3 / 3 moles H2 (needed)] = 2/3
 
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