gatorPredent

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Which is the best way to approach? 1 mole of N2 and 1 mole of H2 are mixed and allowed to react according to the equation N2+3H2 ------> 2NH3. Whats the max number of moles of NH3 that could be produced?
The answer is 2/3 but somehow i got 1/2
Thanks
 
May 15, 2009
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Pre-Dental
Which is the best way to approach? 1 mole of N2 and 1 mole of H2 are mixed and allowed to react according to the equation N2+3H2 ------> 2NH3. Whats the max number of moles of NH3 that could be produced?
The answer is 2/3 but somehow i got 1/2
Thanks
The stochiometric ratio is:

1:3:2
N2:H2:NH3

Since there is only 1 mole of H2 (limiting compound), divide everything by 3 which results in the following ratio:

1/3:1:2/3

This means that 1/3 mole of N2 and 1 mole of H2 will produce 2/3 mole of NH3.
 

MTD52

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I would approach it like this:

Since you need 3moles of H2 to react with 1mole N2, you know that H2 is limiting. Always use the limiting factor.

Since you have 1 mole of H2 and 3 moles of H2 are needed to yield 2 moles of NH3, do this:

1 mol H2 (have) * [ 2 moles NH3 / 3 moles H2 (needed)] = 2/3
 
OP
gatorPredent

gatorPredent

10+ Year Member
Nov 9, 2008
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Florida
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Pre-Dental
those are both good ways to approach this problem. Thank you kindly!