GenChem question

[pbure9]

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In a galvanic cell, Zn(s) + Cu2+(aq) ---> Zn2+(aq) + Cu(s), where E= +1.1V

If 48,000 C of charge are produced in 10 min, what is the mass of Cu deposited?

(1F = 96,000C/mole electrons)

I understand how to work all this out, but for some reason I don't get how they get moles of copper here.

Let me know if posting the answer will help
Thanks!

 

[gabe85]

Cu2+ + (2e-) ------> Cu

In 1 mole of Cu there is 2 moles of electrons.... 1 mole Cu/2 Mole e-

I think that's right. 👍

 

[pbure9]

Cu2+ + (2e-) ------> Cu

In 1 mole of Cu there is 2 moles of electrons.... 1 mole Cu/2 Mole e-

I think that's right. 👍

right.. i think i just had a complete mental block.
So then you'd get 48,000/96,000 to get .5 mole e-? Then that get you 1/2 x .5 = .25 moles of Cu. I was having trouble seeing that . Sounds good
thanks man

And if anyone wants to practice this question, answers 16g

 

[gabe85]

That's right...I remember doing this Kaplan problem.