Quantcast

General Chem question Please explain

This forum made possible through the generous support of SDN members, donors, and sponsors. Thank you.

ManzRDH

Dinene RDH, BA
10+ Year Member
15+ Year Member
Joined
Sep 9, 2003
Messages
50
Reaction score
0

Members don't see this ad.
Can someone explain the steps for this:

Water is formed by adding 4.0g of H2(g) to and excess of O2(g). If 27 grams of H2O are recovered what is the % yield for the rx?
A- 25%
B-50%
C-75%
D-100%
E- cannot be determined from the info

Thanks for your help
 

HuyetKiem

Senior Member
10+ Year Member
15+ Year Member
Joined
Apr 16, 2004
Messages
811
Reaction score
0
ManzRDH said:
Can someone explain the steps for this:

Water is formed by adding 4.0g of H2(g) to and excess of O2(g). If 27 grams of H2O are recovered what is the % yield for the rx?
A- 25%
B-50%
C-75%
D-100%
E- cannot be determined from the info

Thanks for your help

2H2 + O2 --- > 2H2O
4g of H2 would yield 36g of water

But in you case, only 27g of water are recovered. So the % yield for the rx is:
27/36 = 75%
 

ManzRDH

Dinene RDH, BA
10+ Year Member
15+ Year Member
Joined
Sep 9, 2003
Messages
50
Reaction score
0
HuyetKiem said:
2H2 + O2 --- > 2H2O
4g of H2 would yield 36g of water

But in you case, only 27g of water are recovered. So the % yield for the rx is:
27/36 = 75%
thank you for your help
 
Top