General Chemistry Practice Problem

[paymaant]

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12. In the reaction of silver nitrate (AgNO3) with sodium chloride (NaCl), how many grams of silver chloride (AgCl) will be produced from 100 grams of silver nitrate when it is mixed with an excess of sodium chloride? The equation for the reaction is as follows:
AgNO3 + NaCl –> AgCl + NaNO3

a. 0.589 grams
b. 84.4 grams
c. 107.9 grams
d. 169.9 grams
e. 58.9 grams

I calculated the answer to be E but apparently the answer is B !!

Can anyone assist me in figuring this problem out? Thanks!

 

[trocha86]

Hi I got B as my answer The way I did it is as following:
Mwt of Silver nitrate= ~170
so there for I have 100g silver nitrate that was given / 170 g silver nitrate Mwt= ~.58mol Silver nitrate
but now we need the grams of silver chloride
so I set up : .58 mol silver nitrate x 1 mole AgCl/ 1 mol AgNo3 (mole to mole ratio) = .58 mol AgCl
Mwt AgCl= 143g
.58 mol AgCl x 143 g AgCl/ 1 mol AgCl= ~ 82.94 which is closest to B

I hope you understand what I did its hard to explain it through text lol
🙂

 

[paymaant]

OOO Now I see what I did wrong. Thanks for your help! 🙂

 

[trocha86]

No problem anytime! 🙂