Genetic question

[ngozi85e]

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Please help guys 🙂

"Assuming independent assortment, the possible number of different gamete types from 3 homologous pair is....?"

 

[neefs]

I would say 1, but I'm not sure I understand the question exactly. I think you could think of the three homologous gene pairs like "AAbbCC" or any other combo of 3 genes with both alleles for each gene being the same. The only gamete you can get out of that is AbC.

Hope this helps!

 

[theun4given]

But do the genes have to be homozygous? Couldn't three homologous pairs be AaBbCc, and aren't gametes just one expression of the trait, so for example Aa could donate either A or a, Bb could donate either B or b, and so on... Making the number of possible gametes be 6. Am I understanding thsi correctly?

 

[neefs]

Yeah you could be right on that, except if it is that way I think the total possible number would be 2^3 = 8.

 

[ngozi85e]

thanks guys, 8 was the correct answer. So i guess the point to remember is the homologus pr produce 2^n gametes. What would be the case for heterozygous pairs?

 

[xoangelxo]

are u sure the answer is 8??..i thought the equation is 2^n, where n= the number of heterozygous pairs...all of these are homozygous pairs...maybe im wrong though??

 

[bxs023100]

ya i thought it was 2^n for heterozygous pairs. not homologous

 

[AaBbZz]

The answer is 8 , 2^n, because they are talking about homologous pairs (one from each parent, father and mother) which could mean they could have either heterozygous or homozygous alleles.
I think you are confusing the definetions of homoLOGous with homoZYGous. Hope this helps