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Genetic

Discussion in 'DAT Discussions' started by Glycogen, Jun 17, 2008.

  1. Glycogen

    2+ Year Member

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    Do you guys know what is the concept and how do we calculate these type of problems?
    I do have the answer to this but I'm sure whether is right or wrong!
    And there is a very similar Q on DAT ample test on ada site.Please come up with explanation.Thanks and here is the Q:

    Assuming that linkage does not occur how many type of gametes can be produced from an organism with genotype AaBbCcdd?
     
  2. osimsDDS

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    Hey glyco, i came across questions like this many times...iam pretty sure what you do is you count the probability for every genotype...Heterozygotes are 2 and homozygotes are 1...so you have 3 heterozygotes and 1 homozygous (dd)...so you multiply 2x2x2x1=8
     
  3. Glycogen

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    Thank you osims and so the answer is 8 which seems to be right.Though, they have it in this format--> 2^3=8 !
     
  4. ak47

    ak47 flossy flossy
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    use the formulate 2^n where n=number of heterozygote genes
    so it would be 2^3=8
     
  5. osimsDDS

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    yea sorry i suck at math so i just like multiplying out the numbers, but yea either way your counting only the heterozygotes
     
  6. Glycogen

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    Thank you all.Very much helpful.
     

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