B = Black
b = brown
A=normal pigment
a = albino
Experiment 1:
A female hamster with BBAA is crossed with a male hamster bbaa
Experiment 2:
Female offspring from the cross in experiment 1 were backcrossed to the bbaa parent. The distribution of offspring is as follows: black (66), brown (34), white (100).
What is the frequency of recombination between the two loci?
Answer: 34.
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Lets see...
Experiment 1: BBAA * bbaa = BbAa
Experiment 2: then BbAa * bbaa = 25% each of BbAa, Bbaa, bbAa, bbaa. This means that half are white, 1/4 are black, 1/4 are brown.
So they must be linked since they do not display the above distribution. Knowing now that they are linked, how do I proceed?
b = brown
A=normal pigment
a = albino
Experiment 1:
A female hamster with BBAA is crossed with a male hamster bbaa
Experiment 2:
Female offspring from the cross in experiment 1 were backcrossed to the bbaa parent. The distribution of offspring is as follows: black (66), brown (34), white (100).
What is the frequency of recombination between the two loci?
Answer: 34.
----------------
Lets see...
Experiment 1: BBAA * bbaa = BbAa
Experiment 2: then BbAa * bbaa = 25% each of BbAa, Bbaa, bbAa, bbaa. This means that half are white, 1/4 are black, 1/4 are brown.
So they must be linked since they do not display the above distribution. Knowing now that they are linked, how do I proceed?