grignard reaction question

This forum made possible through the generous support of SDN members, donors, and sponsors. Thank you.
Get help with your application

Use all the free resources available to you from SDN: articles, guides, expert advising, forums discussions, and school research.

yoyohomieg5432

Full Member
10+ Year Member
Advertisement - Members don't see this ad
this is from AAMC 10.

The answer is C. I understand why the grignard attacks the carbonyl and forms 2 Ph bonds there. I'm confused on why the OH in the back carbon is replace with OMgBr? I can understand it for the front carbon because after the carbonyl is attacked a carbanion forms and a MgBr can bond to neutralize that.


Also, after treatment with H30+, what causes MgBr to leave and OMgBr ----> OH?
 
Last edited:
this is from AAMC 10.

The answer is C. I understand why the grignard attacks the carbonyl and forms 2 Ph bonds there. I'm confused on why the OH in the back carbon is replace with OMgBr? I can understand it for the front carbon because after the carbonyl is attacked a carbanion forms and a MgBr can bond to neutralize that.


Also, after treatment with H30+, what causes MgBr to leave and OMgBr ----> OH?

Grignard reagents are super strong bases. The Grignard reagent will strip away the H+ in OH, leaving the MgBr cation ionically bonded to the O-. That's why you never use water as a solvent in Grignard reaction. I think diethyl ether is the standard solvent.

The final treatment with H3O+ will remove the MgBr cation and reform the OH bond.
 
Grignard reagents are super strong bases. The Grignard reagent will strip away the H+ in OH, leaving the MgBr cation ionically bonded to the O-. That's why you never use water as a solvent in Grignard reaction. I think diethyl ether is the standard solvent.

The final treatment with H3O+ will remove the MgBr cation and reform the OH bond.

sorry forgot to post the question. OP is updated.

IF the MgBr is a strong base, why doesn't it take the H from the OH and make HMgBr and O-?
 
sorry forgot to post the question. OP is updated.

IF the MgBr is a strong base, why doesn't it take the H from the OH and make HMgBr and O-?

You're mistaken, MgBr is not the Grignard reagent (strong base) -- PhMgBr is the Grignard reagent. You can effectively look at PhMgBr as a Ph- anion. MgBr is the cation that is left over when Ph- strips away the H+ in OH to form the phenyl hydrocarbon .