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Grignard
Started by ChrisM07
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It will always deprotonate any remotely acidic H, such as on an alcohol or a terminal alkyne (which makes an acetylide)
Yep...generally pka of around 25 and lower gets deprotonated. What's I think is important is that you understand that the Grignard is an excellent nucleophile/super strong base. If you understand that you can pretty much extrapolate how it reacts in any scenario.
This is not a grinard reaction. This is a wittig reaction with an ylide acting as a nucleophile. If I am not mistaken, forming a c-c double bond.
This is not a grinard reaction. This is a wittig reaction with an ylide acting as a nucleophile. If I am not mistaken, forming a c-c double bond.
I was going to say the same thing. I don't think there's any case in which a grinard can eliminate the oxygen all together. In all cases, there will always be an alcohol present where there used to be a ketone.
Ah this makes more sense now that I see the answer choices. Your question was, "How do I know if a grinard forms 1) alcohol/alkyl substituent or 2) double bond."
A grinard by itself will always form 1).
A grinard followed by dehydration (H2SO4) will form 2).
I think the confusing part is that a grinard by itself will still use H2SO4 but remember that it's diluted so you really have H3O+. It's just not written as part of the grinard in answer choice E. Thus, the confusion when you see the second step.

