Problem: Consider radioactive nuclide X. If 88% of a pure sample decays in 24 hours, what is the half-life?
The way DAT Destroyer answers it is by the following table:
Time Amount
0 X
? X/2
? X/4
24 1/8
(not sure how well this table will look in this thread but the values under time is 0, ?, ?, and 24. The values under amount is X, X/2, X/4, 1/8.
They get 1/8 from the 12% thats left of the decay but i dont know why they are using X/2 and X/4 or why the time is cut up into 4ths. I thought i just find out what the total time of the decay is by doing 24/.88 to get about 27 hours in total and then do half of 27 to get half life. Is a decay not a constant rate?
The way DAT Destroyer answers it is by the following table:
Time Amount
0 X
? X/2
? X/4
24 1/8
(not sure how well this table will look in this thread but the values under time is 0, ?, ?, and 24. The values under amount is X, X/2, X/4, 1/8.
They get 1/8 from the 12% thats left of the decay but i dont know why they are using X/2 and X/4 or why the time is cut up into 4ths. I thought i just find out what the total time of the decay is by doing 24/.88 to get about 27 hours in total and then do half of 27 to get half life. Is a decay not a constant rate?