Hardy-Weinberg Question please help

[EpicDentist]

I am unsure as to how A was calculated, and how the .954 calculated for A is related to the sum of the alleles = 1 equation for the calculation of a.


Thanks for the help.

Coloration in a species had been previously shown to behave as a single-locus, two-allele system with incomplete dominance. Data for 1612 individuals are given below:
White-spotted (AA) =1469 Intermediate (Aa) = 138 Little spotting (aa) =5



(¦)A = (2 * (1469) + (138))/(2 * (1469 + 138 + 5)) = .954 or 95.4%
(¦)a = 1 - .954 = .046 or 4.6%

---

Members don't see this ad.

 

[EpicDentist]

Anyone?

 

[Golfguy]

It looks as if the percentage for A is incorrectly swapped with phenotype (since it includes the incomplete (heterozygous) groups.