hardy wiesn

[pistolpete007]

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If 16% of population was autosomal recessive what is homozygous dominant?
So q^2=.16 so q=.04 therefore p=.96(dominant allele) but to find homozygous dominant it has to be .96^2=0.9216=92.16%

This doesn’t really make sense because if u comine the homozygous dominat and homozygous recessive you get 108%....and every1 in a population can only be 100% can some1 explain what im doing wrong?

 

[Mstoothlady2012]

If 16% of population was autosomal recessive what is homozygous dominant?
So q^2=.16 so q=.04 therefore p=.96(dominant allele) but to find homozygous dominant it has to be .96^2=0.9216=92.16%

This doesn’t really make sense because if u comine the homozygous dominat and homozygous recessive you get 108%....and every1 in a population can only be 100% can some1 explain what im doing wrong?

This doesn't mean that 16% of the population is homozygous recessive. They are just saying that 16% of the population has recessive allelle. which means q^2 + 2pq = 0.16, since q^2 + 2pq + p^2 = 1, p^2 = 0.84.

 

[HoangDDS]

So they were asking for population homo dominant. And you were give homo recessive allele as 16% which is q=.16 . Therefore p = .84 via p + q = 1. Thus, p^2 which is the frequency of homo dominant is .71 (.84 *.84 = .71) .

You can double check your answer by using p^2 + 2pq + q^2 = 1

q = .16 ---> q^2 = .03
2pq = 2(.16)(.84) = .27
p = .84 ---> p^2 = . 71

.03 +. 27 + .71 = 1

71% should be your frequency of homo dominant. To get an actual population number -- multiple by total population .

 

[Mstoothlady2012]

I didn't even double check my math 🙄 so stupid. Yours makes sense 👍

 

[pistolpete007]

So they were asking for population homo dominant. And you were give homo recessive allele as 16% which is p=.16 . Therefore q = .84 via p + q = 1. Thus, q^2 which is the frequency/population of homo dominant is .71 (.84 *.84 = .71) .

You can double check your answer by using p^2 + 2pq + q^2 = 1

p = .16 ---> p^2 = .03
2pq = 2(.16)(.84) = .27
q = .84 ---> q^2 = . 71

.03 +. 27 + .71 = 1

71% should be your frequency of homo dominant. To get an actual population number -- multiple by total population .


HOLD UP NOW IM REALLLLYY CONFUSED i thought the first response made more sense....because U WERENT GIVEN HOMOZYGOUS RECESSIVE u were u just given the fact that u have recessive allele whethere it be homozygous or heterozygous so wouldnt it make more sensxe to look Q^2 + 2PQ =.16 therefore q^2 being .84?

 

[pistolpete007]

and if it was homozygous recessieve it wouldnt be p=.16 it would be p^2=.16 therefore making p=.4


ne1 else\?

 

[bumpski20]

If 16% of population was autosomal recessive what is homozygous dominant?
So q^2=.16 so q=.04 therefore p=.96(dominant allele) but to find homozygous dominant it has to be .96^2=0.9216=92.16%

This doesn't really make sense because if u comine the homozygous dominat and homozygous recessive you get 108%....and every1 in a population can only be 100% can some1 explain what im doing wrong?

I think thats where you messed up. if q^2 is .16 then q = 0.4 not 0.04.

this is how I did it... q = .16 so P = .84 so p^2 = .71 or 71%

 

[Mstoothlady2012]

So they were asking for population homo dominant. And you were give homo recessive allele as 16% which is p=.16 . Therefore q = .84 via p + q = 1. Thus, q^2 which is the frequency/population of homo dominant is .71 (.84 *.84 = .71) .

You can double check your answer by using p^2 + 2pq + q^2 = 1

p = .16 ---> p^2 = .03
2pq = 2(.16)(.84) = .27
q = .84 ---> q^2 = . 71

.03 +. 27 + .71 = 1

71% should be your frequency of homo dominant. To get an actual population number -- multiple by total population .


HOLD UP NOW IM REALLLLYY CONFUSED i thought the first response made more sense....because U WERENT GIVEN HOMOZYGOUS RECESSIVE u were u just given the fact that u have recessive allele whethere it be homozygous or heterozygous so wouldnt it make more sensxe to look Q^2 + 2PQ =.16 therefore q^2 being .84?

HoangDDS did it right. He just misworded the first sentence. Yes you are not given homozygous recessive, you are given the % of recessive allele = q = 0.16

 

[HoangDDS]

HoangDDS did it right. He just misworded the first sentence. Yes you are not given homozygous recessive, you are given the % of recessive allele = q = 0.16

hehe, thanks msthoothlady for catching that. Yah, so if q=0.16 then p=.84, just square it to get frequency of homo dom. 😎

 

[klutzy1987]

I get a different answer than you 2. The way i see it if .16 are homo recessive then your q value is equal to the square root of that which is .4. If .4 is your q then p+q=1 and therefore p=.6 Now if p=.6 then your homozygous dominant would be .6squared or .36. Thats how i see it if i am wrong somone please let me know what i did wrong.

 

[baedero1]

q^2=0.16
q=0.4

p=0.6
p^2=0.36

36% homo dominant

 

[DRHOYA]

In regards to the wording of the question. When they say certain people of the population are "autosomal recessive".....doesn't that mean Q-squared......b/c in order to be expressing the autosomal recessive trait, then you hvae to be homozygous recessive...right??

 

[Mstoothlady2012]

In regards to the wording of the question. When they say certain people of the population are "autosomal recessive".....doesn't that mean Q-squared......b/c in order to be expressing the autosomal recessive trait, then you hvae to be homozygous recessive...right??

I see what you are saying, but I think the question doesn't specifically use word homozygous recessive, so I am not sure if we can just assume that they are homozygous & that they are expressing recessive trait. All it is says is that 16% population is autosomal recessive, meaning those 16% of the population have atleast 1 recessive allele.

Pistol do you wanna post the answer? so that if I am wrong, I don't make a fool out of myself😳. The way I see it, its not homozygous recessive. But I am not 100% sure. The question might be pulling a trick on us 😎

 

[pistolpete007]

hhaah im not sure what the answer is thats why i asked...one of my buddies whose studying for the mcats asked me on facebook so i thought i'd post it here