Help... anyone

[MariaMaria]

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Can anyone tell me why the answer is c and not a?

What is the hybridization of a nitrogen atom if
it forms two​

σ two π bonds?
A. sp
B. sp2​

C. sp​

3​

D. sp3d2


And this one... why not d... the answer is b.

A 12-volt battery with an internal resistance of
1-​

Ω resistor. Which of the following is the
current in amperes that flows in the circuit.
A. 4
B. 3
C. 9
D. 12​

E. 48

 

[KHE]

Can anyone tell me why the answer is c and not a?

What is the hybridization of a nitrogen atom if
it forms two​

σ two π bonds?
A. sp
B. sp2​

C. sp​

3​

D. sp3d2


And this one... why not d... the answer is b.

A 12-volt battery with an internal resistance of
1-​

Ω resistor. Which of the following is the
current in amperes that flows in the circuit.
A. 4
B. 3
C. 9
D. 12​

E. 48

I will attempt a stab at this...though it has been a while....

In the first question, I think it is asking for the hybridization if it forms two single bonds, not one double bond. Two sigma bonds and two unshared electrion pairs of a nitrogen atom would result in a tetrahedral arrangement and sp3 hybridization.

In the second question, I think you are correct. Ohms law would predict a current of 12, not 3 unless I'm completely forgetting the forumla for Ohm's law.

 

[OATeater]

The Nitrogen question is wrong: nitrogen doesn't form 4 bonds it only forms 3. And its hybridization with 4 groups (the lone electron paris) is sp3...i think.


You're also correct for the resistance:

V = IR

 

[MariaMaria]

You guys are the best! Thanks and Happy New Year!

 

[NCOD]

A double bond is formed by one sigma bond and one pi bond... so this representation is a nitrogen atom with two double bonds. ( X = N = X ) Although, it's not the most stable nitrogen formation, it can happen, and the hybridization is linear, or sp.


And yes, V=IR is Ohm's Law and the current should be 12 amps.

-Hope that helps.

 

[MariaMaria]

Thanks!

You know I can't even believe that they have the wrong answers on that test. Amazing!