30.0 mL of 0.20 M Ba(OH)2 is required to neutralize 25 mL of citric acid (H3C6H5O7). What is the molarity of the citric acid?
I understand to do N1V1=N2V2 and double the concentration of Ba(OH)2. But after all that they tell me that I have to divide by 3 because there are 3 ionizeable protons on citric acid. Why do we have to divide by 3?
I remember a similar question (#128): 20 mL of 0.012 M Ca(OH)2 is added to 48 mL of HBr, what is the concentration of HBr?
Do you have to divide by 1 in this case, which ends up being the answer if you weren't to divide it anyways? So, my question is do you always divide by the # of ionizeable protons in these types of questions?
Thanks!
I understand to do N1V1=N2V2 and double the concentration of Ba(OH)2. But after all that they tell me that I have to divide by 3 because there are 3 ionizeable protons on citric acid. Why do we have to divide by 3?
I remember a similar question (#128): 20 mL of 0.012 M Ca(OH)2 is added to 48 mL of HBr, what is the concentration of HBr?
Do you have to divide by 1 in this case, which ends up being the answer if you weren't to divide it anyways? So, my question is do you always divide by the # of ionizeable protons in these types of questions?
Thanks!