What would be the percentage yield if 11.85 g of Na2S2O3 were obtained from a reaction mixture containing 12.60 g of Na2SO3 and 5.00 g of S?
Na2SO3 + S --> Na2S2O3
A. 55%
B. 60%
C. 65%
D. 70%
E. 75%
can some please explain this question step by step?
Na2SO3 + S --> Na2S2O3
A. 55%
B. 60%
C. 65%
D. 70%
E. 75%
can some please explain this question step by step?