The problem asks rank in order of increasing acidity. I don't have a picture but I'll describe the compounds.
I. Ketone with two methyl groups
II. Anhydride
III. Ketone with one methyl group and hydrogen attached.
IV. Formaldehyde
Answer is IV<I<III<II. Chad said that it's based on resonance. Anhydride has 3 resonance leading to weakest conjugate base and strongest acid, followed by I and III (but III being stronger with less e- donating group in methyl groups), and IV is weakest acid because it doesn't have alpha hydrogens.
But my problem is in my notes I said that aldehydes are better electrophiles than ketones because they have less electron donating groups and thus have a more partially positive carbonyl. Therefore, aldehydes are more acidic than ketones. In that case, wouldn't the order be I<III<IV<II?
This is really annoying me someone please help me out!!!
I. Ketone with two methyl groups
II. Anhydride
III. Ketone with one methyl group and hydrogen attached.
IV. Formaldehyde
Answer is IV<I<III<II. Chad said that it's based on resonance. Anhydride has 3 resonance leading to weakest conjugate base and strongest acid, followed by I and III (but III being stronger with less e- donating group in methyl groups), and IV is weakest acid because it doesn't have alpha hydrogens.
But my problem is in my notes I said that aldehydes are better electrophiles than ketones because they have less electron donating groups and thus have a more partially positive carbonyl. Therefore, aldehydes are more acidic than ketones. In that case, wouldn't the order be I<III<IV<II?
This is really annoying me someone please help me out!!!