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- Nov 29, 2012
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Okay so in the official MCAT guide Gen Chem section q 27 asks
Given the half reactions
Ag+ + e ---> Ag E0= .80V
Cu----> Cu 2+ + 2e E0=-.34 V
Overall Rxn
Cu + 2Ag+---> Cu2+ + 2e- What is the E Cell
I said Cu is the anode because its getting oxidized and Ag is the cathode becuase it is getting reduced. So Cathode-Anode should give the E0 Cell to be .8-(-.34)= 1.14 V.
However, the correct answer is .46 V. Which would result from just adding the two together.
So is there a difference between when you should subtract Cathode-Anode or use Oxidation +Reduction? This is driving me nuts!!
Given the half reactions
Ag+ + e ---> Ag E0= .80V
Cu----> Cu 2+ + 2e E0=-.34 V
Overall Rxn
Cu + 2Ag+---> Cu2+ + 2e- What is the E Cell
I said Cu is the anode because its getting oxidized and Ag is the cathode becuase it is getting reduced. So Cathode-Anode should give the E0 Cell to be .8-(-.34)= 1.14 V.
However, the correct answer is .46 V. Which would result from just adding the two together.
So is there a difference between when you should subtract Cathode-Anode or use Oxidation +Reduction? This is driving me nuts!!