When D-glucose undergoes hemiacetyl formation, it shows the hydroxyl group on C5 acting as the nucleophile to make the chair formation.
Why doesn't the hydroxyl group on C6 act as the nucleophile also (from the CH2OH), since ring structures are stable in both 5/6 member forms?
Thanks in advance!
Why doesn't the hydroxyl group on C6 act as the nucleophile also (from the CH2OH), since ring structures are stable in both 5/6 member forms?
Thanks in advance!