Hess's Law

This forum made possible through the generous support of SDN members, donors, and sponsors. Thank you.

Dr.9999

Full Member
10+ Year Member
Joined
Jul 22, 2009
Messages
72
Reaction score
1
Here is the problem:

The differing structures of graphite and diamond each have a different ΔH of combustion. The ΔH of combustion for two reactions is given below. Find the ΔH of combustion for the 3rd reaction.

C(graphite)+O2(g)⟶CO2(g)Δ H of combustion -393.5 kJ/mol
C(diamond)+O2(g)⟶CO2(g)Δ H of combustion -395.4 kJ/mol
C(graphite)⟶C(diamond) Δ H of combustion= ????

I thought you take dH product - dH reactant. Since we flipped the second equation -395.4 becomes positive. So 395.4 - (-393.5) = 788.9 kJ/mol

But the answer is 1.9 kJ/mol :/
Isn't a negative - negative = positive?

I don't understand this and its driving me crazy because its soooo simple!!!! :((

Members don't see this ad.
 
For these sorts of problems, I find it easiest to just set it up like a series of equations. Once you flip the C(diamond), dH= +395.4. Therefore you take -393.5 + 395.4 = 1.9 kJ/mol.

For Hess's Law, it is best to line the equations up like above and add them together. Hope that helps, let me know if you still don't get it!
 
Okay thanks that might be easier. I was taught to just take the product and subtract it from the reactant but obviously it didn't work in this example.
 
Top