Hey Dr. Green
Started by jdent
Im not green but hope its good enough for yah lol
159- Very straight forward. If you had Nitrobenzene (NO2 group on a benzene ring) and you added cl2 ccl4 which would be an intermediate. (I dont like any truthfully because it should be meta but whatever)
but you could also just forget about that and say which of these forms shown is least stable. Clearly its A since you have a positive charge on an already partially positive carbon (its partially + already since the NO2 group is pulling electron density towards itself and away from that carbon)
so clearly A is the worst of whats given.
159- Very straight forward. If you had Nitrobenzene (NO2 group on a benzene ring) and you added cl2 ccl4 which would be an intermediate. (I dont like any truthfully because it should be meta but whatever)
but you could also just forget about that and say which of these forms shown is least stable. Clearly its A since you have a positive charge on an already partially positive carbon (its partially + already since the NO2 group is pulling electron density towards itself and away from that carbon)
so clearly A is the worst of whats given.
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I was hoping that you would have an actual question, but I'll answer nonetheless.
159 is answered pretty well in Destroyer, just know that since NO2 is electron withdrawing it destabilized the carbocation. look at attached image.
Theres a phenomenon called hyperconjugation, where the H's from the methyl group donate electron density to stabilize the carbocation.
Although N is more electronegative than C, having an octet satisfied is extremely stabilizing. thus choice B is correct.
Seriously though, just read the answers, they explain pretty well.
If you have a specific question on the answers themseleves, or need clarification i'd be more than happy to help.
159 is answered pretty well in Destroyer, just know that since NO2 is electron withdrawing it destabilized the carbocation. look at attached image.
Theres a phenomenon called hyperconjugation, where the H's from the methyl group donate electron density to stabilize the carbocation.
Although N is more electronegative than C, having an octet satisfied is extremely stabilizing. thus choice B is correct.
Seriously though, just read the answers, they explain pretty well.
If you have a specific question on the answers themseleves, or need clarification i'd be more than happy to help.
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