ok so its a simply E2 reaction with strong or weak base. any other reaction that follow this principle?
If I'm not mistaken, E2 reactions typically happen under strong bases. If it's a weak base, it would favor E1.
Either way, E1 or E2, you would still get a double bond.
Anyone can correct me, since I'm not stellar at ochem but my understanding of this is that..
Different kinds of bases would you give you different products
a unhindered, strong base like NaOCH3 --> yields the Zaitsev, which is the more substituted alkene
a bulky, hindered, strong base like (CH3)3COK --> yields Hoffman, which is a less substituted alkene
They differ in terms of mechanism, which H you are removing to form the double bond.
Check out the following powerpoint that I just googled. Look at slide 22 and 23 (for Zaitsev) vs. 53 and 54 (for Hoffman), the beta hydrogen that you remove is different so you get different alkene products.
http://www.google.com/url?sa=t&sour...lazOAw&usg=AFQjCNEF8_ybSpGbViWHJ4Xct9bUjk5j3Q
Hope that clears up some things
🙂