A Aschematic Full Member 10+ Year Member Joined Oct 10, 2009 Messages 29 Reaction score 0 Feb 28, 2010 #1 Calculate the osmotic pressure π for a concentration difference of 0.1 molar. (Ans 2.5 atm) --- What equation would you use? Members don't see this ad.
Calculate the osmotic pressure π for a concentration difference of 0.1 molar. (Ans 2.5 atm) --- What equation would you use? Members don't see this ad.
2 299678 Feb 28, 2010 #2 Osmotic pressure = MRT * i i = 1 so 0.1 * 0.0821 * 273 = about 2.5 Upvote 0 Downvote
A azar87 MD 2 Be 15+ Year Member Joined Apr 17, 2008 Messages 303 Reaction score 0 Feb 28, 2010 #3 easy way to remember is Pi=MARTI pi=symbol for osmotic pressure m=molarity r=gas constant t=temp i=van hoft factor Upvote 0 Downvote
easy way to remember is Pi=MARTI pi=symbol for osmotic pressure m=molarity r=gas constant t=temp i=van hoft factor
R redchesus Full Member 15+ Year Member Joined Oct 13, 2007 Messages 659 Reaction score 321 Feb 28, 2010 #4 kpark102 said: Osmotic pressure = MRT * i i = 1 so 0.1 * 0.0821 * 273 = about 2.5 Click to expand... is i necessarily 1? it doesn't say what the solute is and why is temperature at 273 K? (that's 0 C)... I always assume room temp if not given a temp (298 K) can some explain? Upvote 0 Downvote
kpark102 said: Osmotic pressure = MRT * i i = 1 so 0.1 * 0.0821 * 273 = about 2.5 Click to expand... is i necessarily 1? it doesn't say what the solute is and why is temperature at 273 K? (that's 0 C)... I always assume room temp if not given a temp (298 K) can some explain?
Mycuspidissharp Full Member 10+ Year Member 15+ Year Member Joined Jun 16, 2008 Messages 13 Reaction score 0 Feb 28, 2010 #5 (0.1)(0.0821)(273)(1) = 2.24133 (0.1)(0.0821)(298)(1) = 2.44658 ~ 2.5 [room temp is correct I would say] Upvote 0 Downvote
(0.1)(0.0821)(273)(1) = 2.24133 (0.1)(0.0821)(298)(1) = 2.44658 ~ 2.5 [room temp is correct I would say]