How do you know when london dispersion forces become stronger than dipole dipole

[Jay20155555]

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in one of chads videos quizzes it said this for an answer

These 3 compounds are very different in molecular weight and therefore the determining factor will be molecular weight rather than polarity. H2Te is significantly heavier than the other 2 choices and will therefore have significantly greater London Dispersion forces than the other 2 and the greatest overall intermolecular forces.

the other two choices were H2S, and H2Se

 

[Jay20155555]

how do you measure when the magnitude of the mass overtakes the dipole dipole forces?

 

[FeralisExtremum]

There aren't really significant polarity differences between H2Te molecules (or H2S molecules, or H2Se molecules), which is why London Dispersion forces are basically your only force present. Therefore, when comparing strictly in terms of London Dispersion forces, you look at molecular weight. There is no (significant) dipole-dipole interaction here.