how do you take the anti-log without a calc?

[clockworkin]

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Im working with a organic problem that is dealing with the henderson hasselbach equation and the solution says 2=log(salt/acid) then the next step is saying take the anti log and you get 100=salt/acid..........I dont get where the 100 came from? Please help

 

[vindicate]

log(10)=1
log(100)=2

10^1 = 10
10^2 = 100

 

[UndergradGuy7]

Im working with a organic problem that is dealing with the henderson hasselbach equation and the solution says 2=log(salt/acid) then the next step is saying take the anti log and you get 100=salt/acid..........I dont get where the 100 came from? Please help

10^ and log(x) cancel each other. So 10^log(x) = x

2=log x
10^2 = x
100 = x

 

[tommyngu]

[FONT=Verdana, Arial, Helvetica][SIZE=-1]y = logax <==> [/SIZE].[FONT=Verdana, Arial, Helvetica][SIZE=-1]x = ay

[/SIZE].converting between logarithms and exponents
sorry. subcripts and superscripts don't work here. it's y = log base a of X is the same as x = a^y