S sanguinee Full Member 7+ Year Member Joined May 14, 2014 Messages 122 Reaction score 19 Jan 15, 2015 #1 Members don't see this ad. Why does the OCH3 group on carbon 1 of the right ring get reduced to an OH? This is part of the solution, so we don't know that CH3OH is a byproduct of the reaction. I only thought hydrolysis would cleave the B-1,4 linkage.
Members don't see this ad. Why does the OCH3 group on carbon 1 of the right ring get reduced to an OH? This is part of the solution, so we don't know that CH3OH is a byproduct of the reaction. I only thought hydrolysis would cleave the B-1,4 linkage.
S sanguinee Full Member 7+ Year Member Joined May 14, 2014 Messages 122 Reaction score 19 Jan 17, 2015 #2 bump Upvote 0 Downvote
S sanguinee Full Member 7+ Year Member Joined May 14, 2014 Messages 122 Reaction score 19 Jan 18, 2015 #3 hi does anyone understand this Upvote 0 Downvote
Cawolf PGY-2 10+ Year Member Joined Feb 27, 2013 Messages 3,469 Reaction score 2,287 Jan 18, 2015 #4 It would be more helpful if you posted the whole reaction. If I had to guess, the ether at carbon 1 on the right-side sugar is also hydrolyzed. You just need to track the water. There is a R-O-CH3 at the start and then you add in H2O to produce R-OH and CH3OH. It is likely just a secondary hydrolysis reaction that is occurring in addition to the separation of the sugar linkage. Upvote 0 Downvote
It would be more helpful if you posted the whole reaction. If I had to guess, the ether at carbon 1 on the right-side sugar is also hydrolyzed. You just need to track the water. There is a R-O-CH3 at the start and then you add in H2O to produce R-OH and CH3OH. It is likely just a secondary hydrolysis reaction that is occurring in addition to the separation of the sugar linkage.