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This problem is really bugging me. I was helping my brother do his high school physics online homework and I can not figure this one out..I really thought I understood this stuff to..
A block with a mass of 20 kg is held in equilibrium on an incline of angle θ = 30.0° by the horizontal force, F, as shown in Figure 4-31. Find the magnitude of F.
Force F is just running parallel to the inclined plane pushing on the block.
Here's how I solved it (wrong)
The normal force is the Y-component of gravitational force. Fn would be mgcos30 which is 173N
The F1 pushing the block is only in the x-direction so that has to equal the x-component of gravity since a=0. mgsin30 is 100N
The answer key says 113N and 227N for the answers respectively. Can someone explain?
A block with a mass of 20 kg is held in equilibrium on an incline of angle θ = 30.0° by the horizontal force, F, as shown in Figure 4-31. Find the magnitude of F.
Force F is just running parallel to the inclined plane pushing on the block.
Here's how I solved it (wrong)
The normal force is the Y-component of gravitational force. Fn would be mgcos30 which is 173N
The F1 pushing the block is only in the x-direction so that has to equal the x-component of gravity since a=0. mgsin30 is 100N
The answer key says 113N and 227N for the answers respectively. Can someone explain?