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MCAT4life1

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Hey All!
I've been going over some of my practice MCAT problems. My private tutor gave me this one and I'm a bit confused on how to proceed. Any words of wisdom?

For the hydrolysis of acetyl phosphate under the conditions prevailing in the body, ΔG = -41 kJ·mol-1. If the phosphorylation of acetic acid (the reverse of the hydrolysis of acetyl phosphate) was driven by coupling to the hydrolysis of ATP at pH = 7, what is the minimum amount of ATP molecules (in moles) that would have to be hydrolyzed to form 1.0 mol acetyl phosphate molecules by the phosphorylation of acetic acid? (1) ADP3-(aq) + HPO42-(aq) + H+(aq)
rtarrow.gif
ATP4-(aq) + H2O(l)
ΔG = + 30.5 kJ (
2) NADH(aq)
rtarrow.gif
NaD+(aq) + H+(aq) + 2 e-
ΔG = -158.3 kJ
(3) 1/2 O2(g) + 2 H+(aq) + 2 e-
rtarrow.gif
H2O(l)
ΔG = -61.9 kJ

Thanks!
 
Im guessing but I would say two base on the equation given in the question and equation 1.
I do not know why you need equation 2 and 3.
Since the phosophorylation of acetic acid has a G of POSITIVE 41 kJ/mol. You need at least NEGATIVE 42 kJ/mol....
Since the hydrolysis of 1 ATP is -30.5KJ, I say you need to hydrolysis 2 moles of ATP.
 
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